Marbles In A Jar Probability

Two marbles are drawn without replacement.

Marbles in a jar probability.

You can arrange the marbles however you like but each marble must be in a jar. The chance is 2 in 5 but after taking one out the chances change. For example if the answer is 2 3 the response should be 0 67. Pose questions to the children about each of the jars and the probability of picking certain colored marbles.

What is the maximum probability. A jar contains 4 black marbles and 3 red marbles. Total number of marbles 23 4 27 marbles p green marble of green marbles of marbles total 4 27 0 148 so the probability is 4 27 which is about a 14 8 chance. Answer in decimal rounded off to 2 decimal places.

Remember there is one less marble in the jar. What is the probability that you pick 3 green no red 1 of each at least 1 blue marble if a jar contains 5 blue 3 green and 4 red marbles. Place the possible card in front of the jar. Finally multiply the probabilities and reduce to get 1 19.

At least 1 red a jar contains 30 red marbles 12 yellow marbles 8 green marbles and 5 blue marbles. So the probability of getting a blue marble is 13 42. Find the probability of picking green 4 20 then find the probability of picking blue 5 19. If a marble is drawn at random from the jar the probability that it is green is 32.

A jar contains 24 marbles some are green and others are blue. 13 is a prime number and 42. The total number of marbles in the second jar is 42 marbles and the total number of blue marbles in the jar is 13. If we got a red marble before then the chance of a blue marble next is 2 in 4.

P getting a color other than red p 25 55 455 probability of this happening 3 times in a row is found by 455 455 455 094 example 2. Have the children take turns answering the questions and placing the probability cards in front of each jar after each of the questions.